Fix the mistake: Differentiation ② (Composite Functions, Trigonometric Functions, Exponential and Logarithmic Functio
Differentiating Composite Functions ①: The Chain Rule
The derivative of a composite function consisting of two functions, such as y = f(g(x)), is
{f(g(x))}′ = f'(g(x))·g'(x) (chain rule)
Remember it as “differentiate the outer function × differentiate the inner function.”
Example ① Find y' for y = (3x+1)⁵.
Solution: Outer function = u⁵ → 5u⁴; inner function = 3x+1 → 3.
y' = 5(3x+1)⁴ · 3 = 15(3x+1)⁴
Solution: Outer function = u⁵ → 5u⁴; inner function = 3x+1 → 3.
y' = 5(3x+1)⁴ · 3 = 15(3x+1)⁴
Example ② Find y' for y = √(x²+1).
Solution: (u^{1/2})' = u^{−1/2}/2; (x²+1)' = 2x.
y' = (1/(2√(x²+1)))·2x = x/√(x²+1)
Solution: (u^{1/2})' = u^{−1/2}/2; (x²+1)' = 2x.
y' = (1/(2√(x²+1)))·2x = x/√(x²+1)
Key Point
- “Differentiate the outside × differentiate the inside”
- The most important formula, used with powers, √, exponential functions, and logarithms
Practice Problems
- Find y' for y = (2x−5)⁴
- Find y' for y = √(3x+2)
Answers and Explanations
- Answer:8(2x−5)³
- Answer:3/(2√(3x+2))
Previous and next lessons in this course
- Previous lesson: Fix the mistake: Differentiation ② (Composite Functions, Trigonometric Functions, Exponential and Logarithmic Functio
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Math (Math III): related lessons
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- Fix the mistake: Differentiation ② (Composite Functions, Trigonometric Functions, Exponential and Logarithmic Functio
- Fix the mistake: Applications of Differentiation ① (Tangents, Monotonicity, and Extrema)