Before moving on to the formulas for sectors, let us review the formulas for the circumference and area of a circle and pi π. Once these are understood, sectors can be calculated easily as “parts of a circle.”
Pi π
For every circle, the value of circumference ÷ diameter is always constant, approximately 3.14159…. This constant value is called pi and is represented by the Greek letter π.
π = circumference / diameter ≒ 3.14
From middle school onward, calculations often leave pi as π. Remember, “do not change π to 3.14” (use 3.14 only when specifically instructed).
Circumference
For a circle with radius r and diameter d = 2r, its circumference ℓ is:
ℓ = 2πr (from the radius)
ℓ = πd (from the diameter)
Area of a Circle
The area S of a circle with radius r is:
S = πr²
If π is taken as 3.14, the area of a circle with radius 5 cm is 3.14 × 25 = 78.5 cm². If π is left as it is, write 25π cm².
For a circle with radius 8 cm, find the following. Leave π as it is.
(1) Circumference (2) Area
Solution:
(1) ℓ = 2π × 8 = 16π (cm)
(2) S = π × 8² = 64π (cm²)
Calculations Using the Diameter
When the diameter is given, first convert it to the radius (÷2), or use ℓ = πd directly.
Example: Circle with diameter 10 cm → circumference = π×10 = 10π cm, area = π×5² = 25π cm².
Find the circumference and area of a circle with diameter 14 cm. Leave π as it is.
Solution:
Radius = 14÷2 = 7 cm.
Circumference = 2π × 7 = 14π (cm) (or πd = 14π is also acceptable)
Area = π × 7² = 49π (cm²)
- Pi π ≒ 3.14159…. In middle school, leave it as π unless instructed otherwise.
- Circumference = 2πr = πd
- Area of a circle = πr²
- For a problem beginning with the diameter, first convert it to the radius.
Practice Problems
- Find the circumference and area of a circle with radius 6 cm, leaving π in the answers.
- Find the circumference and area of a circle with diameter 20 cm, leaving π in the answers.
- A circle has circumference 12π cm. Find its radius and area, leaving π as it is.
Answers and Explanations
- Answer: Circumference 12π cm, area 36π cm²
Explanation: ℓ = 2π×6 = 12π, S = π×6² = 36π. - Answer: Circumference 20π cm, area 100π cm²
Explanation: Radius = 10. ℓ = 2π×10 = 20π, S = π×10² = 100π. - Answer: Radius 6 cm, area 36π cm²
Explanation: 2πr = 12π → r = 6. S = π×6² = 36π.