Junior high entrance exam / Surplus-and-Deficiency Problems 2 / 4

Excess-and-Shortage Method ② Finding the Number of Children from Two Patterns of Conditions

Excess-and-Shortage Method ② Finding the Number of People from Two Conditions

Learn application problems involving seat assignments and group formation, which commonly appear in the excess-and-shortage method.

Excess-and-Shortage Problems with Seats and Groups

Example Problem
Students are seated on benches in a gym. If 6 students sit on each bench, 4 students cannot sit; if 8 students sit on each bench, 2 benches are left unused. How many benches are there?

Solution:Let the number of benches be N.
① Six students each: number of students=6×N+4
② Eight students each: number of students=8×(N-2)=8N-16 (since 2 benches are left over, N-2 benches are used)
③ Since the number of students is the same,
 6N+4=8N-16
 20=2N
 N=10 benches
④ Number of students=6×10+4=64 students

How to Interpret "Benches Are Left Over"

"m benches are left over" means that no one is sitting on the last m benches. Set up the equation as number of students=number of people per bench ×(N-m).

Key Points
  • "○ people cannot sit" means a "shortage," just as when there are not enough items.
  • When "m benches are left over," express it as "8×(N-m)," for example.
  • Connect the two equations with an equals sign and find the number of benches N.

Practice Problems

  1. Students are put on buses. If 40 students ride each bus, 2 buses are left over; if 30 ride each bus, 20 students cannot ride. How many buses are there?
  2. Children are put into tents. If 4 children enter each tent, 3 children cannot enter; if 5 enter each tent, 1 tent is left over. How many children are there?
  3. If 5 students sit on each bench, 9 cannot sit; if 7 sit on each bench, 1 bench is left over. How many benches are there?

Answers and Explanations

  1. Answer:There are 8 buses
    Explanation: If 40 students ride each bus, 2 buses are left over; if 30 ride each bus, 20 students cannot ride. If there are N buses: 40×(N-2)=number of students (2 buses are left over, so N-2 buses are used), 30N+20=number of students (20 students cannot ride with 30 per bus). 40(N-2)=30N+20. 40N-80=30N+20. 10N=100. N=10 buses. Number of students=30×10+20=320. Check: 40×(10-2)=40×8=320✓
  2. Answer:There are 19 children
    Explanation: With 4 children per tent, 3 cannot enter; with 5 per tent, 1 tent is left over. If there are N tents: 4N+3=number of children, 5×(N-1)=number of children (since 1 tent is left over, everyone fits in N-1 tents). 4N+3=5N-5. 8=N. Number of children=4×8+3=32+3=35. Check: 5×(8-1)=5×7=35✓
  3. Answer:There are 7 benches
    Explanation: With 5 students per bench, 9 cannot sit; with 7 students per bench, 1 bench is left over. If there are N benches: 5N+9=number of students, 7×(N-1)=number of students (since 1 bench is left over, everyone sits on N-1 benches). 5N+9=7N-7. 16=2N. N=8 benches. Number of students=5×8+9=40+9=49. Check: 7×(8-1)=7×7=49✓

Questions and answers for this lesson

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