Moving one step beyond limits of sequences, we now study the limit of a function f(x). We examine the behavior of f(x) as x approaches a arbitrarily closely.
As x approaches a arbitrarily closely, if f(x) approaches a fixed value α arbitrarily closely, we write
lim_{x→a} f(x) = α. “x → a” means “x approaches a” (x need not equal a itself).
Limits of the Four Basic Operations
When lim f(x) = α and lim g(x) = β:
- lim (f ± g) = α ± β, lim (kf) = kα
- lim (fg) = αβ, lim (f/g) = α/β (β≠0)
For a continuous function, lim_{x→a} f(x) = f(a).
Example ①
(1) lim_{x→2} (x² + 3x − 1) (2) lim_{x→0} (x + 5)/(2x + 3)
Solution:(1) Substitute: 4+6−1 = 9 (2) 5/3
(1) lim_{x→2} (x² + 3x − 1) (2) lim_{x→0} (x + 5)/(2x + 3)
Solution:(1) Substitute: 4+6−1 = 9 (2) 5/3
The 0/0 Indeterminate Form
When both the numerator and denominator are 0, direct substitution is impossible. Factor and cancel.
Example: lim_{x→2} (x²−4)/(x−2) = lim (x+2) = 4
Example ②
lim_{x→1} (x²−3x+2)/(x−1)
Solution:(x−1)(x−2)/(x−1) → x−2 → −1
lim_{x→1} (x²−3x+2)/(x−1)
Solution:(x−1)(x−2)/(x−1) → x−2 → −1
Key Points
- x → a means “approach a” (x need not equal a)
- For a continuous function, lim f(x) = f(a)
- 0/0 → factor and cancel
- If √ is included, rationalize
Practice Problems
- lim_{x→3} (x²−9)/(x−3)
- lim_{x→0} (√(x+4)−2)/x
- lim_{x→−1} (x²+3x+2)/(x+1)
Answers and Explanations
- Answer:6
(x−3)(x+3)/(x−3) → x+3 → 6. - Answer:1/4
Rationalize. 1/(√(x+4)+2) → 1/4. - Answer:1
(x+1)(x+2)/(x+1) → x+2 → 1.