Mathematics A / Counting Cases ① (Permutations) 5 / 6

Number of Cases⑤ Summary

Summary of the Number of Cases
  • Multiplication principle, addition principle, and inclusion-exclusion principle
  • Permutations nPr = n!/(n−r)!
  • Circular permutations (n−1)!, necklaces (n−1)!/2
  • Permutations with repetition n^r
  • Permutations with identical objects n!/(p!q!…)

Comprehensive Practice Problems

  1. Arrange 4 men and 3 women. How many arrangements have no two women adjacent?
  2. How many six-digit integers can be formed using the six digits 0,1,1,2,2,2, with the first digit not 0?
  3. How many ways can 8 people be divided into 3 teams of 4, 2, and 2 (with the teams distinguished)?

Answers

  1. Arrange the 4 men (4!=24), then place the women in 3 of the 5 spaces: 5P3=60 → 24×60=1440 arrangements
  2. Total: 6!/(1!×2!×3!)=60 arrangements. When the first digit is 0: 5!/(2!×3!)=10 arrangements → 50 integers
  3. 8C4×4C2×2C2=70×6×1=420 arrangements

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