Junior high entrance exam / Counting Problems (Junior High School Entrance Examination) 2 / 4

Counting Cases ② Permutations and Combinations

Counting② Permutations and Combinations

Let us understand the difference between “arrangements (permutations)” and “selections (combinations).” The key point is whether or not order matters.

Permutations (Arrangements)

Choose and arrange r items from n items (order matters):
nPr = n×(n-1)×…×(n-r+1)

Example 1
In how many ways can 3 people be selected from 5 people and arranged in a line?

Answer:
5×4×3=60 ways

Combinations (Selections)

Choose r items from n items (order does not matter):
nCr = nPr ÷ r!

Example 2
In how many ways can 3 people be selected from 5 people?

Answer:
5C3 = (5×4×3)÷(3×2×1) = 60÷6 = 10 ways
Key Points
  • “Order matters” → permutation (nPr)
  • “Only selection matters; order does not” → combination (nCr)
  • nCr = nC(n-r) (symmetry)

Practice Problems

  1. In how many ways can 4 people be selected from 6 people?
  2. In how many ways can a chairperson, vice-chairperson, and secretary be selected from the five people A, B, C, D, and E?

Answers and Explanations

  1. Answer: 15 ways
    Explanation: 6C4=6C2 (symmetry) = (6×5)÷(2×1) = 30÷2 = 15 ways.
  2. Answer: 60 ways
    Explanation: The positions of chairperson, vice-chairperson, and secretary are distinct, so order matters (permutation). 5P3=5×4×3=60 ways.

Questions and answers for this lesson

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